-5q^2-20q+8800=0

Solution for -5q^2-20q+8800=0 equation:

-5q^2-20q+8800=0

a = -5; b = -20; c = +8800;
Δ = b2-4ac
Δ = -202-4·(-5)·8800
Δ = 176400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{176400}=420$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-420}{2*-5}=\frac{-400}{-10}
=+40
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+420}{2*-5}=\frac{440}{-10}
=-44
$